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0=4x^2-5x+3
We move all terms to the left:
0-(4x^2-5x+3)=0
We add all the numbers together, and all the variables
-(4x^2-5x+3)=0
We get rid of parentheses
-4x^2+5x-3=0
a = -4; b = 5; c = -3;
Δ = b2-4ac
Δ = 52-4·(-4)·(-3)
Δ = -23
Delta is less than zero, so there is no solution for the equation
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